(5/x^2-x-2)-(2/x^2-4)=4/x^2+3x+2

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Solution for (5/x^2-x-2)-(2/x^2-4)=4/x^2+3x+2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/(x^2)-x-(2/(x^2))-2+4 = 3*x+4/(x^2)+2 // - 3*x+4/(x^2)+2

5/(x^2)-x-(3*x)-(2/(x^2))-(4/(x^2))-2-2+4 = 0

5/(x^2)-x-3*x-2*x^-2-4*x^-2-2-2+4 = 0

-4*x-x^-2 = 0

-x*(x^-3+4) = 0

1*x^-3 = -4 // : 1

x^-3 = -4

-3 < 0

1/(x^3) = -4 // * x^3

1 = -4*x^3 // : -4

-1/4 = x^3

x^3 = -1/4 // ^ 1/3

x = -(1/4)^(1/3)

-x = 0

-1*x = 0 // : -1

x = 0

x in { 0} 

x = -(1/4)^(1/3)

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